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化合物CptRh（PMe3）Cl2（Cpt=η5-1,3-tBu2C5H3）在DMF溶液中与[Et4N]2Se6反应,形成半夹心结构铑硒化合物CptRh（PMe3）（Se4）.用nBu3P作为亲核试剂,与CptRh（PMe3）（Se4）进行消去反应,得到相应的铑硒三元环化合物CptRh（PMe3）（Se2）.CptRh（PMe3）Cl2与[nBu4N]2Te5在DMF溶液中反应,只能生成半夹心结构铑碲三元环化合物CptRh（PMe3）（Te2）,而在热的二氯甲烷中则形成Te-Te键之间插入了亚甲基的产物CptRh（PMe3）（TeCH2Te）.用红外光谱,EI-质谱和1H,13C,31P,103Rh核磁共振谱以及元素分析表征了这些新化合物.
The compound CptRh (PMe3) Cl2 (Cpt = η5-1,3-tBu2C5H3) was reacted with [Et4N] 2Se6 in DMF to form a semi-sandwich rhodium selenide CptRh (PMe3) (Se4). Using nBu3P as the nucleophile, (PMe3) Cl2 reacted with [nBu4N] 2Te5 in DMF solution to form the corresponding half-sandwich of rhodium-selenide (PMe3) (Se2) with CptRh (PMe3) (Te2), while in hot methylene chloride, a methylene product, CptRh (PMe3) (TeCH2Te), was inserted between the Te-Te bonds. EI-MS and 1H, 13C, 31P, 103Rh NMR spectra and elemental analysis.