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一、轨迹为直线——明确加速度方向由于轨迹是直线,所以加速度方向必须与轨迹共线,或者加速度为零,即带电粒子的运动性质是匀加速直线运动、匀减速直线运动或匀速直线运动,结合力的特点,确定加速度方向后问题迎刃而解。例1如图1,平行板电容器的两个极板与水平地面成一角度,两极板与一直流电源相连。若一带电粒子恰能沿图中所示水平直线通过电容器,则在此过程中,该粒子()A.所受重力与电场力平衡B.电势能逐渐增加C.动能逐渐增加D.做匀变速直线运动
First, the trajectory of a straight line - a clear acceleration As the trajectory is a straight line, so the acceleration direction must be collinear with the trajectory, or acceleration is zero, that is, the movement of charged particles is uniform acceleration linear motion, uniform deceleration linear motion or uniform linear motion, Combining the characteristics of the acceleration direction to determine the problem solved. Example 1 As shown in Figure 1, two plates of a parallel plate capacitor are angled to horizontal ground and the plates are connected to a DC power source. If a charged particle can just pass through the capacitor in the horizontal straight line as shown in the figure, in the process, the particle () A. balance of gravity and electric field force B. Potential energy gradually increased C. Kinetic energy gradually increased D. Do uniform Variable speed linear motion