解方程 sin5x=sin4x。解法一:因为与a有相同的正弦值的弧度数x的集合是{x|x=kπ+(-1)~ka,k∈Z},所以原方程可以化成 5x=kπ+(-1)4x (k∈Z) 解之得:x=kπ/5+(-1)~(k+1) 所以原方程的解集是{x|2= 解法二:原方程等价为sin4x=sin5x,m同解法一得:4x=kπ+(-1)~k5x 解之得:x=kπ/4+(-1)~(k+1)5(k∈z) Solve the equation sin5x=sin4x. Solution one: because the set of radians x with the same sine value as a is {x|x=kπ+(-1)~ka,k∈Z}, the original equation can be reduced to 5x=kπ+(-1) The solution of 4x (k∈Z) is: x=kπ/5+(-1)~(k+1) so the solution set of the original equation is {x|2= solution two: the original equation is equivalent to sin4x=sin5x, m is the same as the solution: 4x=kπ+(-1)~k5x The solution is: x=kπ/4+(-1)~(k+1)5(k∈z)