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本文通过一道高中数学题的初中解法来说明教学中如何寻找最适合学生最近发展区的通性通法,让学生体会数学的魅力,以期引发读者更多的思考.一、原题及其解答如图1所示,在正方形ABCD中,E、F分别是CB、CD延长线上的点,已知EF=BE+DF,求∠EAF的度数.解记正方形ABCD的边长为a,BE=b,DF=c,∠EAB=α,∠FAD=β.在Rt△ADF中
This article through a high school mathematics junior high school solution to explain how to find the most suitable for students in the most recent development of Tong Tong Tong law, so that students appreciate the charm of mathematics, in order to lead readers to think more. As shown in Fig. 1, in the square ABCD, E and F are the points on the extended line of CB and CD respectively, and the degree of ∠EAF is known as EF = BE + DF. b, DF = c, ∠EAB = α, ∠FAD = β. In RtΔADF