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人民教育出版社出版的高中平面解析几何全一册(必修)《教学参考书》是高中数学教师正确把握教材的重要参考资料.本人在讲授“圆”时发现,《教学参考书》对教材一道习题的参考答案有值得商榷的地方.不揣浅陋,谈谈自己的不成熟的看法,供各位同仁参考. 教材第七十一页,习题五的第十四题: 等腰三角形的顶点是A(4,2),底边一个端点是B(3,5),求另一端点的轨迹方程,并说明它的轨迹是什么. 参考答案:“所求的轨迹方程为。‘+y’-8。-4y+10=0(x / 3,x / 5) 轨迹是以A为圆心,/元为半径的圆,但除去两点” 对其解答,本人认为有不当之处: 若设等腰三角形底边另一端点为C(1,y) 依据答案,当。一3时,代人所求轨变方程中去:
The high school level analytical geometry book (required) published by the People’s Education Press is an important reference material for high school mathematics teachers to correctly grasp the teaching materials. When I taught “Circle”, I found that the “Teaching Reference Book” was used together with textbooks. The reference answers to the exercises are worthy of discussion. Don’t be shy, talk about your own immature views, for your colleagues to refer to. Textbook page 71, Problem 5 of the fourteenth problem: Isosceles triangle vertex is A ( 4,2), one end of the bottom edge is B(3,5), find the trajectory equation of the other end point, and explain what its trajectory is. Refer to the answer: “The trajectory equation to be sought is ’.+y’-8’ -4y+10=0 (x / 3, x / 5) The trajectory is a circle with A as its center and / is a radius, but with two points removed,” I would like to answer it. I think there is something wrong: If we set isosceles The other end of the triangle is C(1,y). According to the answer, when. At 3 o’clock, the generation’s pursuit of the orbital equation goes: