例1用如图1所示电路测电源电动势和内阻的实验中,测量值ε、γ和真实值ε0、γ0的大小关系是ε______ε0、γ0______γ0(填“大于”、“等于”、“小于”) 解测量ε、γ的原理是U =ε-Ir.此实验的误差来源是因为伏特表的分流分用.伏特表测得的电压值是真实值,因而测量值和真实值的表达式应分别为: U=ε-IAr, U=ε(IA+IV)ra. Example 1 In the experiment of measuring the power EMF and internal resistance with the circuit shown in Fig. 1, the magnitude relationship between the measured values ​​ε, γ and the real values ​​ε0, γ0 is ε______ε0, γ0______γ0 (fill in “greater than”, “equal to”, and “less than”. The principle of the solution to the measurement of ε and γ is U = ε-Ir. The source of error for this experiment is the splitting of the voltmeter. The voltage measured by the voltmeter is a real value, and therefore the expression of the measured value and the real value should be They are: U=ε-IAr, U=ε(IA+IV)ra.