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Since the zeros of sin x are O,±π,±2π,…,we can factorize sin x: sin x=ax(x-π) (x+π) (x-2π) (x+2π) … and using limx→0sinx/x=1 we can determine the value of a:sinx=x· (1-x/π)· (1+x/π)· (1-x/2π)·(1+x/2π)…=x· (1-x2/π2)·