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一、在化简和求值中的应用例1已知a~2-b=a(a-1)+2．求代数式(a~2+b~2)/2-ab的值．解：由a~2-b=a(a-1)+2．得a-b=2．∴(a~2+b~2)/2-ab=(a~2+b~2-2ab)/2= (a-b)~2/2=2~2/2=2．
I. Application in Simplification and Evaluation Example 1 It is known that a~2-b=a(a-1)+2. Find the value of the algebraic expression (a~2+b~2)/2-ab. Solution: From a~2-b=a(a-1)+2. A-b=2. ∴(a~2+b~2)/2-ab=(a~2+b~2-2ab)/2=(a-b)~2/2=2~2/2=2.