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高中阶段,计算离开地面任意高度h处的重力加速度值,是学生学习过程中最常见的问题.一般的处理方法是忽略地球自转的影响,利用物体的重力等于物体所受的万有引力,即可求得g′/g=R~2/(R+h)~2,其中g′、g、R分别表示高度h处的重力加速度值、地球表面处的重力加速度值和地球半径.下面具体分析一道试题.例题.在地球表面,某物体用弹簧测力计竖直悬挂且静止时,弹簧测力计的示数为F_1=160 N.把该物体悬挂在同一弹簧测力计上,置于竖直向上加速的航天器中,加速度大
In high school, calculating the value of gravitational acceleration at any height h away from the ground is the most common problem in student learning, and the general approach is to ignore the effect of the Earth’s rotation and use the gravitational force of an object equal to the gravitational force on the object Where g ’, g and R represent the gravitational acceleration at height h, the value of gravitational acceleration at the Earth’s surface, and the radius of the Earth, respectively, as follows: g’ / g = R ~ 2 / (R + h) Example. In the Earth’s surface, an object with a spring force gauge hanging vertically and stationary, the spring force gauge shows F_1 = 160 N. The object is suspended in the same spring force gauge, placed on the vertical In a spacecraft that accelerates straight up, the acceleration is high