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一、真题再现及试题评述16.(本小题满分14分)如图1,在三棱锥S-ABC中,平面SAB⊥平面SBC,AB⊥BC,AS=AB,过A作AF⊥SB,垂足为F,点E,G分别是棱SA,SC的中点.求证:(1)平面EFC∥平面ABC;(2)BC⊥SA.试题以三棱锥为载体,主要考查线面平行的判定定理、面面平行的判定定理、面面垂直的性质定理、线面垂直的判定定理及性质定理,检验了学生的空间想象能力和推理论证能力.
First, the true question reproduction and questions comments 16. (The subject of a full 14 points) Figure 1, in the triangular pyramid S-ABC, the plane SAB⊥ plane SBC, AB ⊥ BC, AS = AB, A for AF ⊥ SB, Defective foot as F, point E, G are the midpoint of the edge SA, SC respectively. Proof: (1) Plane EFC∥ plane ABC; (2) BC⊥SA. Test questions with triangular pyramid as the carrier, the main line surface parallel Judgment theorem, judgment theorem of face parallelism, property theorem of face vertical, judgment theorem of face vertical and property theorem test students’ spatial imagination ability and reasoning argumentation ability.