当涉及到多对等位基因控制某一性状的遗传题时,学生往往不易找到恰当的方法解题,很多情况下会采用例举法,或用各个选项依次代入题干(若是选择题的话)来检验选项是否正确,但是,这样会比较费时间,且不适用于非选择题。下面介绍由受精作用和配子形成规律列方程或不等式速解此类遗传题的方法。例1在玉米中,有色种子必需具备A、B、D三个基因,否则无色,A与a、B与b、D与d这三对等位基因自由组合。现有一个有色植株甲同已知基因型的三个植株杂交 Students often find it hard to find a proper way to solve a problem when it comes to allelic control of multiple traits. In many cases, the method of enumeration is used, or the options are used in turn (if multiple-choice questions are used) To verify that the options are correct, however, this can be time-consuming and does not apply to non-choice questions. Here’s how to formulate a regular column equation or inequality to solve such genetic problems by fertilization and gametes. Example 1 In corn, colored seeds must have A, B, D three genes, otherwise colorless, A and a, B and b, D and d of the three pairs of alleles freely combined. One existing colored plant A is crossed with three plants of known genotype