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利用IR光谱和Raman光谱等实验手段,对25℃时Rb2Ca[B4O5(OH)4]2·8H2O的溶解及相转化过程进行了初步探索,结果表明,Rb2Ca[B4O5(OH)4]2·8H2O溶于水后,硼在溶液中主要以B(OH)3和[B(OH)4]-的形式存在,残留固相由开始的无定形水合三硼酸钙,最终部分转变为Ca2[B3O3(OH)5]2·8H2O晶体。
The dissolution and phase transformation of Rb2Ca [B4O5 (OH) 4] 2 · 8H2O at 25 ℃ were investigated by means of IR and Raman spectroscopy. The results showed that the reaction of Rb2Ca [B4O5 (OH) 4] 2 · 8H2O After being dissolved in water, the boron is mainly present in solution in the form of B (OH) 3 and [B (OH) 4] -. The residual solid phase is converted from the starting amorphous calcium triborate to the Ca2 [B3O3 OH) 5] 2 · 8H2O crystals.