论文部分内容阅读
高中化学教材上册,有这样三道热化学方程式: C_((固))+O_(2(气))=CO_(2(气))+393.5千焦C_((固))+H_2O_((气))=CO_((气))+H_(2(气))-131.3千焦S_((固))+O_(2(气))=SO_(2(气))+296.6千焦笔者认为这三道热化学方程式不严密。因为碳和硫都有同素异形体,方程式中的碳和硫没有注明它所属的晶型。因为反应热不仅与物质有关,还与它所属的晶型有关。
High school chemistry textbooks, there are three thermochemical equations: C_ ((solid)) + O_ (2 (gas)) = CO_ (2 (gas)) + 393.5 kJ C_ ((solid)) + H_2O_ ((gas )) = CO_ (gas) + H_ (2 (gas)) -131.3 kJ S_ ((solid)) + O_ (2 (gas)) = SO_ (2 (gas)) + 296.6 kJ The three thermochemical equations are not strict. Because both carbon and sulfur have allotropes, the carbon and sulfur in the equation do not indicate the crystal form it belongs to. Because the heat of reaction is not only related to the substance, it is also related to the crystal form it belongs to.