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2009年全国高考数学试卷理(I)第22题:设函数f(x)=x3+3bx2+3cx有两个极值点x1、x2,且x1∈[-1,0],x2∈[1,2].
2009 National College Entrance Examination Mathematics Test (22): Let f (x) = x3 + 3bx2 + 3cx have two extreme points x1, x2, and x1∈ [-1,0], x2∈ [1 ,2].