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The electrochemical reduction mechanism of hafnium ion(Ⅳ) was studied in NaCl–KCl–K_2HfCl_6 melts on a molybdenum electrode. The cyclic voltammetry study shows that Hf(Ⅳ) is reduced to hafnium metal in double two-electron process, that is: Hf(Ⅳ)+2e~-→Hf(Ⅱ) and Hf(Ⅱ)+2e~-→Hf, and the electrochemical reduction of Hf(Ⅳ) process was diffusion-controlled. The diffusion coefficients were calculated at several temperatures, and the results obey the Arrhenius law. According to the relationship of lnD versus 1/T,the corresponding activation energy was determined to be 158.8 kJ ·mol~(-1). The square wave voltammetry results further confirm the reduction mechanism of hafnium.
The electrochemical reduction mechanism of hafnium ion (Ⅳ) was studied in NaCl-KCl-K_2HfCl_6 melts on a molybdenum electrode. The cyclic voltammetry study shows that Hf (Ⅳ) is reduced to hafnium metal in double two-electron process, that is: Hf (Ⅳ) + 2e ~ - → Hf (Ⅱ) and Hf (Ⅱ) + 2e ~ - → Hf, and the electrochemical reduction of Hf (Ⅳ) process was diffusion-controlled. The diffusion coefficients were calculated at several temperatures, and the results obey the Arrhenius law. According to the relationship of lnD versus 1 / T, the corresponding activation energy was determined to be 158.8 kJ · mol -1. The square wave voltammetry results further confirm the reduction mechanism of hafnium.