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1一卜列各式与竺2二相等的是( x+y A.业卫上鱼B (x+y)+5 2x--y 2x+y c一宜卫立D (x+y)2 护子 xZ+尹 2.计算~止生.+ m+2 4 mZ一4 的结果是( A .m+2 B.m一Zc一三一D一卫止 m+Zm一2 沪 1计算号+(a一翻的正确结果是‘ A 4. 年增长 三一B .Ic一卫二D一1 。+1 aesl 某城市2002年国民
The difference between 1 and 2 is equal to (x+y A. Guardian Fish B (x+y)+5 2x--y 2x+yc Yi Wei D (x+y)2. Sub-xZ+ Yin 2. Calculations ~ Suspensions. + m+2 4 mZ-4 The result is (A.m+2 Bm-Zc-31 D-guard-m+Zm-2 Hu-1 calculation number + (a-a The correct result of the turn is ’A 4. The annual growth of Trinity B.Ic is a guardian of two D-1’s. +1 Aesl of a city in 2002 nationals