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为了对合成氨系统进行热力学分析,首先需要知道含氨混合气的热力学函数值。然而这些数据又往往不够准确,缺乏足够的实验依据。本文从已发表的实测含氨混合气的基础数据出发,拟合成计算焓 H、熵 S 和有效能 B 的公式:H=(0.58075-0.3188x+0.908x~2)T-149.35-874.3x+31.48x~2;S=(0.58075-0.3188x+0.908x~2)1 nT-4.050+0.990x-5.40x~2;B=(0.58075-0.3188x+0.908x~2)(T-2981nT)+(1107.8-1169.5x+1641.5x~2)。混合气体组成为:CH 45.2%,Ar9.2%,N_2:H_2=1:3,氨含量 X=0—16%。压力:300at。并进一步根据所推出的公式,绘制成含氨混合气的有效能图。应用该图对中型氨厂流程进行分析,能很快地找到降低系统能耗的关键所在。
In order to conduct a thermodynamic analysis of an ammonia system, it is first necessary to know the thermodynamic function values of the ammonia-containing gas mixture. However, these data are often not accurate enough, lack of sufficient experimental basis. Based on the published data of measured ammonia-containing gas mixture, the formula for calculating enthalpy H, entropy S and effective energy B is obtained: H = (0.58075-0.3188x + 0.908x ~ 2) T-149.35-874.3x (T-2981nT) + 31.48x ~ 2; S = (0.58075-0.3188x + 0.908x ~ 2) 1 nT-4.050 + 0.990x-5.40x ~ 2; B = (0.58075-0.3188x + 0.908x ~ 2) + (1107.8-1169.5x + 1641.5x ~ 2). The mixed gas composition is: CH 45.2%, Ar 9.2%, N 2: H 2 = 1: 3, ammonia content X = 0-16%. Pressure: 300at. And further according to the formula introduced, drawn into the ammonia-containing mixture of the effective energy map. Using the diagram to analyze the medium-sized ammonia plant process can quickly find the key to reducing system energy consumption.