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在分子束条件下利用化学发光技术研究了亚稳态惰性气体原子He（23S1）和Ne（3P0，2）与NH3碰撞的解离激发反应．He（23S1）与NH3的反应中观察到NH（A－X，c－a，c－b），NH＋（B－X）和H*－Balmer发射．对NH（A－X，c－a）的谱图进行了拟合．分析NH（c－b）谱发现NH（c）倾向于生成具有f对称性的转动能级，NH3可能是经由一个NH2中间体分两步解离，这与121．6nm光解NH3时的倾向性正好相反．利用参比反应测得生成NH（A，c）的速度为k＝1．0×10－11cm3·s－1．He（23S1）与NH3生成的NH（A，v’＝1）的转动激发比v’＝0时要高，根据含角动量守恒的相空间理论，其生成过程可能具有较大的解离半碰撞参数．Ne（3P0，2）与NH3反应只有NH（A－X，c－a）发射，NH（A，c）的振转布居可由简单相空间理论三体解离模式解释．
Under the condition of molecular beam, chemisorption technique was used to study the dissociation reaction of collisions of metastable inert gas atoms He (23S1) and Ne (3P0,2) with NH3. NH (A-X, c-a, c-b), NH + (B-X) and H * -Balmer emission were observed in the reaction of He (23S1) with NH3. The NH (A-X, c-a) spectra were fitted. Analysis of the NH (c-b) spectrum reveals that NH (c) tends to generate a rotational energy level with f symmetry. NH3 may be dissociated in two steps via an NH2 intermediate, which is consistent with the propensity for 121.6 nm photodissociation of NH3 The opposite is true. The rate of NH (A, c) generation was k = 1.0 × 10-11 cm3 · s-1 as measured by the reference reaction. The rotational excitation of NH (A, v ’= 1) generated by He (23S1) and NH3 is higher than that of v’ = 0. According to the phase space theory with angular momentum conservation, the generation of NH (A, Collision parameters. Ne (3P0,2) only react with NH3 to emit NH (A-X, c-a). The population of NH (A, c) can be explained by the simple three-