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采用准经典轨线方法研究了碰撞反应 Ca+RBr(R=CH_3,C_2H_5 和 n-C_3H_7)的矢量相关性质和产物 CaBr 分子的转动取向.计算了不同碰量相关撞能情况下产物分子的转动取向参数和反应物与产物之间的矢分布几率函数.矢量相关由角分布函数 P(θ_r)!P(φ_r)和 P(θ_r,φ_r)以及极化相关微分截面来描述.Ca+CH_3Br 反应产物 CaBr 的 P(θ_r)峰值大于 Ca+C_2H_5Br 和 Ca+n-C_3H_7Br 反应产物 CaBr 的 P(θ_r)峰值.对于反应 Ca+RBr 的 P(θ_r)在φ_=3π/2处的峰值明显大于φ_r=π/2处的峰值.计算结果表明,在碰撞反应过程中,产物 CaBr 分子的转动角动量不仅发生取向,而且沿着垂直于散射面方向发生定向：产物 CaBr 分子强烈地沿着反应物相对速度方向向前散射；产物分子转动角动量的定向和取向将不同程度地影响产物的散射方向.
The quasi-classical trajectory method was used to study the vectorial correlation properties of Ca + RBr (R = CH_3, C_2H_5 and n-C_3H_7) and the rotational orientation of the CaBr product. The molecular rotation Orientation parameter and the probability distribution function between the reactant and the product.The vector correlation is described by the angular distribution function P (θ_r) P (φ_r) and P (θ_r, φ_r) as well as the polarization-dependent differential cross section.The Ca + CH_3Br reaction The peak of P (θ_r) of CaBr product is larger than the peak of P (θ_r) of CaBr reaction product of Ca + C_2H_5Br and Ca + n-C_3H_7Br.The peak of P (θ_r) at φ_ = 3π / 2 is obviously larger than φ_r = π / 2. The calculated results show that during the collision reaction, the rotational angular momentum of the product CaBr molecules not only orient but also orient along the direction perpendicular to the scattering plane: the product CaBr molecule strongly opposes the reactant Scattering in the direction of velocity; the orientation and orientation of the angular momentum of the product molecule will affect the scattering direction of the product to varying degrees.