函数与方程的思想方法1.此问题由于常见的思维定势,易把它看成关于x的不等式进行分类讨论.然而,若变换一个角度以m为主元,记f(m)=(x2-1)m-(2x-1),则问题转化为求一次函数(或常数函数)f(m)的值在区间[-2,2]内恒负时参数x应该满足的条件.要使f(m)0,只要使f(-2)0,f(2)0,即2-(2x The idea of ​​functions and equations 1. This problem is apt to be categorized as a discussion of the inequality of x due to the common thinking tendency. However, if you transform an angle to m as the principal element, remember that f(m) = (x2) -1) m-(2x-1), then the problem is converted to the condition that the parameter x should be satisfied when the value of the first function (or constant function) f(m) is constant in the interval [-2,2]. f(m)0, as long as f(-2)0,f(2)0, ie 2-(2x)