对2013年山东省高考数学试题(理)第22题进行极限思考,能有效避开繁复运算,新颖明了的获得结论.题目(2013年山东试题)椭圆C:(x~2)/(a~2)+(y~2)/(b~2)=1(a>b>0)的左、右焦点分别是F_1,F_2,离心率为(3~(1/2)/2),过F_1且垂直于x轴的直线被椭圆C截得的线段长为1.(1)求椭圆C的方程;(2)点P是椭圆C上除长轴端点外的任一点,连结PF_1,PF_1,设∠F_1PF_2的角平分线PM交C的长轴于点M(m,0),求m的取值范围;(3)在(2)的条件下,过点P作斜率为k的直线l, (2013) Shandong Province Question Elliptic C: (x ~ 2) / (a ​​~ C) (2) In this paper, The left and right focal points of 2, + (y ~ 2) / (b ~ 2) = 1 (a> b> 0) are F_1 and F_2 and the eccentricity is (3 ~ (1/2) F_1 and the line perpendicular to the x-axis is the length of the line segment taken by the ellipse C as 1. (1) Find the equation of ellipse C; (2) Point P is any point on the ellipse C except the long axis end point, , Set the angle bisector of ∠ F_1PF_2 to intersect the major axis of PM at point M (m, 0) and find the range of m; (3) l,