１９９６年加拿大数学奥林匹克试题及解答１．若α，β，γ是ｘ３－ｘ－１＝０的根，计算１＋α１－α＋１＋β１－β＋１＋γ１－γ的值．解设ｆ（ｘ）＝ｘ３－ｘ－１＝（ｘ－α）（ｘ－β）（ｘ－γ）有根α，β，γ，则根据多项式根的有关结论可得如下结果：α＋β＋γ... 1996 Canadian Mathematics Olympiad Questions and Answers 1. If α, β, γ are the roots of x3-x-1 = 0, calculate the value of 1+α1-α+1+β1-β+1+γ1-γ. The solution f(x)=x3-x-1=(x-α)(x-β)(x-γ) has roots α,β and γ. According to the relevant conclusion of the polynomial root, the following results can be obtained: α+β+γ. ..