一、单一函数类1.恒成立问题例1已知函数f(x)=ax~3+cx+d(a≠0)是R上的奇函数,当x=1时f(x)取得极值-2.(1)求f(x)的单调区间和极大值;(2)证明对任意x_1,x_2∈[-1,1],不等式|f(x_1)-f(x_2)|<4恒成立.分析本题是同一函数的最值问题,只需求出函数f(x)在[-1,1]上的最值(或范 First, a single function class 1 constant established problem Example 1 known function f (x) = ax ~ 3 + cx + d (a ≠ 0) is an odd function on R, when x = 1 f (2) We prove that for any x_1, x_2∈ [-1,1], the inequality | f (x_1) -f (x_2) | < 4 constant established. Analysis of the problem is the most value of the same function problem, only need to find out the function f (x) in [-1,1] on the most value