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(2012年中考)某小区装修需要照明,施工人员用两根长均为200m的铝导线将一盏“220V500W”的电灯接在照明电路上。晚上八点施工时,施工人员发现该电灯灯光较暗,于是他用仪表测得该灯泡两端的实际电压为200V,已知铝导线每米长的电阻约为0.02Ω。(计算时不考虑温度对电阻的影响,计算结果取整数),问:(1)灯泡的实际功率是多少?(2)连接灯泡的铝导线上损失的电功率是多少?(3)施工人员发
(2012 mid-term test) A residential decoration requires lighting, construction workers with two 200m long aluminum wire will be a “220V500W ” light connected to the lighting circuit. Construction at eight o’clock in the evening, the construction crew found the light darker, so he measured the actual voltage across the bulb with an instrument of 200V, known resistance per meter long aluminum wire is about 0.02Ω. (Calculated without taking into account the effect of temperature on the resistance, the calculation results take an integer), Q: (1) What is the actual power of the bulb? (2) What is the electrical power lost on the aluminum wire connected to the bulb?