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《数学通报》问题1662,求函数f(x)=sinx+cosx+tanx+cotx+secx+cscx的值域,其解答利用切割化弦和换元法求得值域为(+∞,1-2(2～(1/2)))∪(2+3(2～(1/2)),+∞).
The problem of mathematical notation 1662 is to find the value range of the function f (x) = sinx + cosx + tanx + cotx + secx + cscx. The solution uses the cut- 2 (2 ~ (1/2))) ∪ (2 + 3 (2 ~ (1/2)), + ∞).