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设点Q是直线l:Ax+By+C=0上的一点,点P是坐标平面内的任意一点,d为点P到直线l的距离,则d≤|PQ|.本文介绍利用这一结论解题的方法和技巧.
Let point Q be a point on line l: Ax + By + C = 0, point P is any point in the coordinate plane, d is the distance from point P to line l, then d≤ | PQ | Conclusion of the problem-solving methods and techniques.